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Find out the encumbrance factor and value of the usable FSI from following particulars of the property :
Land area - 533 Sq Sq m
Total built-up area - 205 Sq m
Permissible FSI - 1
Rate of construction cost - Rs. 5000 per Sq m
Rate of land cost - Rs. 2000 per Sq m
Desired rate of return - 9%
Usable carpet area - 155 Sq m
Monthly Rent on carpet area basis - Rs. 50 per Sq m
Usual outgoings - 1/6 of yield
Solution
Cost of construction = 205 x 5000 = 1025000
Cost of FSI used = 205 x 2000 = 410000
Total cost = 1435000
Desired Yield @ 9% = 1435000 x 0.09 =129150
Estimated Yield = 50 x 155 x 12 = 93000
Usual outgoings = 1/6 of yield = 93000/6 = 15500
Net annual yield = 77500
Hence, encumbrance factor = 77500/93000 = 0.833
Usable FSI = 533 - 205 = 328 Sq m
Value of usable FSI = 328 x 0.833 x 2000 = 546448
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Suppose that during the rent of a property the owner earns the income of 60000 on a quarterly basis.
Set the value of this liability at the current moment;
in other words, determine the price of this property, if it was sold at the present moment at the interest rate:
1) of 8% converted on a quarterly basis?
2) of 8% converted on an annual basis?
We have that
1) R = 60000;
i = 0.02;
A = 60000 / 0.02
= 3000000:
Thus, the market value of this property is 3000000.
2) In the case we have a complex annuity,
thus: R = 60000, i = 0.08, c = 0.25 Then
p = 1.08^0.25 - 1 = 0.0194265
A = 60000/0.0194265 = 3088557
In this case the value of this property is 3088557.
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The device, the cost of which is 120000, must be replaced after six years.
It is known that after six years the used equipment could be sold for 20000.
Set the value of the property at the present moment (capitalize the costs) if the interest rate is 10%, which is converted once a
year?
We have that OV = 120000, the replacement costs R = 120000 - 20000 = 100000,
In addition,
i = 0.15;
c = 1/(1/6) = 6 and
p = 1.1^6 - 1 = 0.7716
Then
K = 120000 + (100000/0.7716)
= 249607.4
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